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6k^2-47k+35=0
a = 6; b = -47; c = +35;
Δ = b2-4ac
Δ = -472-4·6·35
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-37}{2*6}=\frac{10}{12} =5/6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+37}{2*6}=\frac{84}{12} =7 $
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